QUIZ 2025 ORACLE PERFECT NEW 1Z1-830 BRAINDUMPS FILES

Quiz 2025 Oracle Perfect New 1z1-830 Braindumps Files

Quiz 2025 Oracle Perfect New 1z1-830 Braindumps Files

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Oracle Java SE 21 Developer Professional Sample Questions (Q42-Q47):

NEW QUESTION # 42
Which of the followingisn'ta correct way to write a string to a file?

  • A. java
    Path path = Paths.get("file.txt");
    byte[] strBytes = "Hello".getBytes();
    Files.write(path, strBytes);
  • B. java
    try (FileOutputStream outputStream = new FileOutputStream("file.txt")) { byte[] strBytes = "Hello".getBytes(); outputStream.write(strBytes);
    }
  • C. None of the suggestions
  • D. java
    try (PrintWriter printWriter = new PrintWriter("file.txt")) {
    printWriter.printf("Hello %s", "James");
    }
  • E. java
    try (BufferedWriter writer = new BufferedWriter("file.txt")) {
    writer.write("Hello");
    }
  • F. java
    try (FileWriter writer = new FileWriter("file.txt")) {
    writer.write("Hello");
    }

Answer: E

Explanation:
(BufferedWriter writer = new BufferedWriter("file.txt") is incorrect.)
Theincorrect statementisoption Bbecause BufferedWriterdoes nothave a constructor that accepts a String (file name) directly. The correct way to use BufferedWriter is to wrap it around a FileWriter, like this:
java
try (BufferedWriter writer = new BufferedWriter(new FileWriter("file.txt"))) { writer.write("Hello");
}
Evaluation of Other Options:
Option A (Files.write)# Correct
* Uses Files.write() to write bytes to a file.
* Efficient and concise method for writing small text files.
Option C (FileOutputStream)# Correct
* Uses a FileOutputStream to write raw bytes to a file.
* Works for both text and binary data.
Option D (PrintWriter)# Correct
* Uses PrintWriter for formatted text output.
Option F (FileWriter)# Correct
* Uses FileWriter to write text data.
Option E (None of the suggestions)# Incorrect becauseoption Bis incorrect.


NEW QUESTION # 43
Given:
java
int post = 5;
int pre = 5;
int postResult = post++ + 10;
int preResult = ++pre + 10;
System.out.println("postResult: " + postResult +
", preResult: " + preResult +
", Final value of post: " + post +
", Final value of pre: " + pre);
What is printed?

  • A. postResult: 15, preResult: 16, Final value of post: 6, Final value of pre: 6
  • B. postResult: 16, preResult: 16, Final value of post: 6, Final value of pre: 6
  • C. postResult: 15, preResult: 16, Final value of post: 5, Final value of pre: 6
  • D. postResult: 16, preResult: 15, Final value of post: 6, Final value of pre: 5

Answer: A

Explanation:
* Understanding post++ (Post-increment)
* post++uses the value first, then increments it.
* postResult = post++ + 10;
* post starts as 5.
* post++ returns 5, then post is incremented to 6.
* postResult = 5 + 10 = 15.
* Final value of post after this line is 6.
* Understanding ++pre (Pre-increment)
* ++preincrements the value first, then uses it.
* preResult = ++pre + 10;
* pre starts as 5.
* ++pre increments pre to 6, then returns 6.
* preResult = 6 + 10 = 16.
* Final value of pre after this line is 6.
Thus, the final output is:
yaml
postResult: 15, preResult: 16, Final value of post: 6, Final value of pre: 6 References:
* Java SE 21 - Operators and Expressions
* Java SE 21 - Arithmetic Operators


NEW QUESTION # 44
Which two of the following aren't the correct ways to create a Stream?

  • A. Stream stream = Stream.empty();
  • B. Stream<String> stream = Stream.builder().add("a").build();
  • C. Stream stream = Stream.of("a");
  • D. Stream stream = Stream.of();
  • E. Stream stream = Stream.ofNullable("a");
  • F. Stream stream = new Stream();
  • G. Stream stream = Stream.generate(() -> "a");

Answer: B,F

Explanation:
In Java, the Stream API provides several methods to create streams. However, not all approaches are valid.


NEW QUESTION # 45
Which of the following statements is correct about a final class?

  • A. It cannot extend another class.
  • B. It cannot be extended by any other class.
  • C. The final keyword in its declaration must go right before the class keyword.
  • D. It must contain at least a final method.
  • E. It cannot implement any interface.

Answer: B

Explanation:
In Java, the final keyword can be applied to classes, methods, and variables to impose certain restrictions.
Final Classes:
* Definition:A class declared with the final keyword is known as a final class.
* Purpose:Declaring a class as final prevents it from being subclassed. This is useful when you want to ensure that the class's implementation remains unchanged and cannot be extended or modified through inheritance.
Option Evaluations:
* A. The final keyword in its declaration must go right before the class keyword.
* This is correct. The syntax for declaring a final class is:
java
public final class ClassName {
// class body
}
* However, this statement is about syntax rather than the core characteristic of a final class.
* B. It must contain at least a final method.
* Incorrect. A final class can have zero or more methods, and none of them are required to be declared as final. The final keyword at the class level prevents inheritance, regardless of the methods' finality.
* C. It cannot be extended by any other class.
* Correct. The primary characteristic of a final class is that it cannot be subclassed. Attempting to do so will result in a compilation error.
* D. It cannot implement any interface.
* Incorrect. A final class can implement interfaces. Declaring a class as final restricts inheritance but does not prevent the class from implementing interfaces.
* E. It cannot extend another class.
* Incorrect. A final class can extend another class. The final keyword prevents the class from being subclassed but does not prevent it from being a subclass itself.
Therefore, the correct statement about a final class is option C: "It cannot be extended by any other class."


NEW QUESTION # 46
Which StringBuilder variable fails to compile?
java
public class StringBuilderInstantiations {
public static void main(String[] args) {
var stringBuilder1 = new StringBuilder();
var stringBuilder2 = new StringBuilder(10);
var stringBuilder3 = new StringBuilder("Java");
var stringBuilder4 = new StringBuilder(new char[]{'J', 'a', 'v', 'a'});
}
}

  • A. stringBuilder3
  • B. stringBuilder4
  • C. stringBuilder2
  • D. stringBuilder1
  • E. None of them

Answer: B

Explanation:
In the provided code, four StringBuilder instances are being created using different constructors:
* stringBuilder1: new StringBuilder()
* This constructor creates an empty StringBuilder with an initial capacity of 16 characters.
* stringBuilder2: new StringBuilder(10)
* This constructor creates an empty StringBuilder with a specified initial capacity of 10 characters.
* stringBuilder3: new StringBuilder("Java")
* This constructor creates a StringBuilder initialized to the contents of the specified string "Java".
* stringBuilder4: new StringBuilder(new char[]{'J', 'a', 'v', 'a'})
* This line attempts to create a StringBuilder using a char array. However, the StringBuilder class does not have a constructor that accepts a char array directly. The available constructors are:
* StringBuilder()
* StringBuilder(int capacity)
* StringBuilder(String str)
* StringBuilder(CharSequence seq)
Since a char array does not implement the CharSequence interface, and there is no constructor that directly accepts a char array, this line will cause a compilation error.
To initialize a StringBuilder with a char array, you can convert the char array to a String first:
java
var stringBuilder4 = new StringBuilder(new String(new char[]{'J', 'a', 'v', 'a'})); This approach utilizes the String constructor that accepts a char array, and then passes the resulting String to the StringBuilder constructor.


NEW QUESTION # 47
......

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